In this picture, you must be aware that the repeating decimal is two digits repeating instead of three. Also, it is important to know your infinite geometric formula as it does come into play in the middle of the problem. Also, be aware that this problem has a whole number in it as well, so in the end, convert the whole number to a fraction that can be added to the answer in order to obtain the true answer to the problem.
Monday, December 9, 2013
Monday, November 25, 2013
Fibbonaci Haiku: Supa Hot Fire
Sweet
Tea
From Mcdonalds
I drink that
Sweet chicken from Tyrone's kitchen
Dang bro that is delicious I TASTE THAT
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| http://zrhbzeds.homeip.net/funny-black-kfc-pictures.html |
Monday, November 18, 2013
SP #5 Unit J Concept 6: DECOMPOSING TERRAWR
HOW TO DO THIS 101
The equation is next to 1) and we are "decomposing" it accordingly. The decomposition is shown to the right of the equation. Bottom of that is me showing the process of getting a common denominator. Basically multiply other factors in order to have the same thing on the bottom. Multiply, exponentiate, etc. correctly and then you will result in a long list of terms, ignoring the bottom terms. Afterwards, add like terms, setting the list equal to the numerator of the original equation. After canceling common terms, such as x and x^2, you will find yourself with 4 sets of equations. Those equations will result in a 5x4 system of equations.
In the bottom picture, after we inputted the equation into the calculator (you should be able to do this) we will find fractions as answers. Now we have to manually solve these by elimination. Let's add the first two equations together and multiply the third equation by 2.Add the third equation and the fourth equation together and now we have two equations to work with. Multiply the resulting equation from adding the first and second together by 4 so we can cancel out 4C as shown below.Below that is how we cancel B when we used the first equation in the above picture. We then find A and plug that in to find B and then vice versa. The bottom left is the answer. This question was ezpz.
SP #4 Unit J Concept 5: Partial Fraction Decomposition
We are doing two things. We are solving backwards to get the original equation, and then decomposing it afterwards. In the below equation, let us get a common denominator. Multiply each factor by the value of the term that it does not have as a denominator. We then add like terms to get the "original equation" for our next step.

This is where the decomposing begins. Separate the equations as shown. Get a common denominator by doing the same thing we did before. Set the equation equal to the original one and add like terms. We will then get a system of 3 equations which we can plug into the matrix. Let us use rref and find A, B, and C and then we will plug in the values as its corresponding term which is the answer at the very bottom leftish.

This is where the decomposing begins. Separate the equations as shown. Get a common denominator by doing the same thing we did before. Set the equation equal to the original one and add like terms. We will then get a system of 3 equations which we can plug into the matrix. Let us use rref and find A, B, and C and then we will plug in the values as its corresponding term which is the answer at the very bottom leftish.
Thursday, November 14, 2013
SV #5 Unit J Concepts 3-4: How to Solve 3-Variable Equations
In this video, we are going to learn how to effectively take 3-step solving to the next level. We must pay attention to not get our signs wrong because that would result in a completely different answer. Be sure to simplify the original equations as best as you can in order to make your life much easier. Be careful and multiply, add, subtract, and divide correctly in order to lead up to the correct answer. Good ol' day chap.
Monday, November 4, 2013
WPP #6 Unit I Concept 3-5: Interest and More Interest (Compound, Continuous, and Investment Application
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Sunday, November 3, 2013
SV #4 Unit I Concept 2: Graphing Functions (Logarithmic)
This video is just like concept 1, but with a vertical asymptote instead. Instead of having the asymptote equal k, we set it the same as h. Therefore, it is also imperative to draw it vertically instead of drawing it horizontally. The other key information we need to derive from these problems are an x-intercept, y-intercept, domain, range, key points, and the graph. The range, for vertical asymptote-oriented functions, is all real numbers. The domain is the varying factor for these functions.
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